Need asap suppose that quiz scores in a beginning statistics class have a mean of 6.4 with a standard deviation of 0.7. using chebyshev's theorem, state the range in which at least 88.9% of the data will reside. do not round your answers.

Given that mean of quiz scores = 6.4 and standard deviation = 0.7

And we need to use Chebyshev's theorem to find the range in which 88.9% of data will reside.

Chebyshev's theorem states that "Specifically, no more than of the distribution's values can be more than k standard deviations away from the mean".

That is

k = 3

So, we want the range of values within 3 standard deviations of mean.

Hence range is [mean -3*standard deviation, mean +3*standard deviation]

                      = [6.4 - 3*0.7 , 6.4+3*0.7]

                      = [6.4 - 2.1 , 6.4+2.1] = [4.3,8.5]

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step-by-step explanation:

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.