Ajar contains 4 red marbles numbered 1 to 4 and 10 blue marbles numbered 1 to 10. a marble is drawn at random from the jar. find the probability the marble is blue or evennumbered.\

Step-by-step explanation:

As per given ,  The jar contains

Red marbles = (R1) , (R2) , (R3) , (R4)

Blue marbles =  (B1) ,   (B2) ,   (B3) ,   (B4) ,   (B5) ,   (B6) ,   (B7) ,   (B8) ,   (B9) ,   (B10) .

Total marbles = 4+10=14

The marbles that has even number = (R2)  , (R4) ,(B2) , (B4) ,  (B6) ,   (B8) , (B10)

=7

Total Blue marbles  = 10

Blue and even marbles = 5

Now , the number of marbles are blue or even numbered :

n(Blue or even )= n(Blue) + n(even)- n(Blue and even)

= 10+7-5 =12

Now , the probability the marble is blue or even numbered will be :

Hence, required probability =

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

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