The coordinates of the vertices of △jkl are j(3,4) k(3,1) l(1,1). coordinates of the vertices of △j’k’l’ are j’(-3,-5) k’(-3,-2) l’(-1,-2). dragon drop the answers into the boxes to correctly complete dragon drop answers into the boxes to correctly complete the statement. a sequence of transformations that maps △jkl to j’k’l’ is a (fill blank) follwed by a (fill blank). answer choices are : rotation of 90 degrees counterclockwise about the origin. rotation of 180 degrees about the origin. translation 1 unit down. translation 1 unit left.

Given coordinates of △JKL are J(3,4) K(3,1) L(1,1) and

△J’K’L’ are J’(-3,-5) K’(-3,-2) L’(-1,-2).

We know, when we rotate a figure about 180 degrees about the origin, the coordinates (x,y) would result (-x,-y).

So, first step should be "Rotation of 180 degrees about the origin."

After rotating 180 degrees about the origin, J(3,4) K(3,1) L(1,1) points would transform to  J(-3,-4) K(-3,-1) L(-1,-1).

Now, we will move 1 unit down. So the new coordinate of (-x,-y) would become (-x, -y-1) and J(-3,-4) K(-3,-1) L(-1,-1) coordinates would transform to exactly J(-3,-4-1) K(-3,-1-1) L(-1,-1-1)  => J’(-3,-5) K’(-3,-2) L’(-1,-2).

And those are the coordinates of transformed triangle △J’K’L’.

So, the steps of transformations are as following:

Setp 1) Rotation of 180 degrees about the origin.

Setup 2) Translation 1 unit down.

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation:

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent