Match the following. 1. the domain set of c = {( 2, 5), (2, 6), (2, 7)} {3, 4, 5, 6} 2. the range set of e = {(3, 3), (4, 4), (5, 5), (6, 6)} domain = {all real numbers}: range = {y: y = 3} 3. the range and domain of f = {(x, y ) | x + y =10} {2} 4. the range and domain of p = {(x, y) | y = 3} domain = range = {all real numbers}

1. The domain set of C = {(2,5),(2,6),(2,7)} is the set of all first elements of the ordered pairs.

Therefore, domain set of C = {2}

2. The range set of E ={(3, 3),(4, 4),(5, 5),(6, 6)} is the set of all second elements of the ordered pairs.

Therefore, range set of E = {3,4,5,6}

3. We need to find the range and domain of F = {(x, y) | x + y = 10}.

Clearly, the domain is the set of all real numbers.

Also, if x is a real number, then 10 - x is also a real number.

We have, x + y = 10

y = 10 - x

So, y is also a real number.

Therefore, range and domain of F = {all real numbers}

4. We need to find the range and domain of P = {(x, y) | y = 3}.

Clearly, the domain is the set of all real numbers.

Since, the y = 3 (the second element of the ordered pair), the range is the singleton set {2}.

Hence, domain = {all real numbers} and range = {y : y = 3}

question:

could we have options?

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it