Check all of the functions that are odd. f(x)=x3-x2 f(x)=x5-3x3+2x f(x) = 4x + 9 f(x)=1/x

A function is odd if and only if:

f(-x) = -f(x)

For every value of x in its domain.

We will see that the odd functions are:

f(x) = x^5 - 3*x^3 + 2*x

f(x) = 1/x

Now we only need to test the above condition for all the given functions:

1) f(x) = x^3 - x^2

Evaluating this in -x we get:

f(-x) = (-x)^3 - (-x)^2 = -x^3 - x^2

Here we can see that:

f(-x) ≠ -f(x)

Thus, this function is not odd.

2) f(x) = x^5 - 3*x^3 + 2*x

Evaluating in -x we get:

f(-x) = (-x)^5 - 3*(-x)^3 + 2*(-x)

      = -x^5 + 3*x^3 - 2*x = -f(x)

This function is odd.

3) f(x) = 4x + 9

Evaluating in -x we get:

f(-x) = 4*(-x) + 9 = -4*x + 9

while:

-f(x) = -( 4*x + 9) = -4*x - 9

Thus: f(-x) ≠ -f(x)

Then this function is not odd.

4) f(x)  = 1/x

Evaluating in -x we get:

f(-x) = 1/(-x) = -1/x

Then we can see that:

f(-x) = -f(x)

Thus this function is odd.

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The odd function among the given choices are:

Step-by-step explanation:

We have to check which of the following function is odd.

We know that a function f(x) is said to be an odd function if:

1)

on replacing x with -x we have:

Hence, the given function f(x) is not an odd function.

2)

on replacing x with -x we have:

Hence, function f(x) is an odd function.

3)

on replacing x with -x we have:

Hence, function f(x) is not an odd function.

4)

on replacing x with -x we have:

Hence, the given function f(x) is an odd function.

b. x- 48 =120

step-by-step explanation:

answer: 48

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