Abaseball player hit 62 home runs in a season. of the 62 home runs, 24 went to right field, 17 went to right center field, 9 went to center field, 10 went to left center field, and 2 went to left field.(a)what is the probability that a randomly selected home run was hit to right  field? (b)what is the probability that a randomly selected home run was hit to left  field? (c)was it unusual for this player to hit a home run to left  field? explain.

we know that The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so  

P=size of the event space/size of the sample space

Part a) What is the probability that a randomly selected home run was hit to right field?

size of the sample size=62

size of the event space=24

P=24/62> 12/31=0.3871> P=38.71%

the answer Part a) is

The probability is equal to 38.71%

Part b) What is the probability that a randomly selected home run was hit to left field?

size of the sample size=62

size of the event space=2

P=2/62> 1/31=0.0323> P=3.23%

the answer Part b) is

The probability is equal to 3.23%

Part c) Was it unusual for this player to hit a home run to left field?

Yes, it was unusual since the probability of hitting a home run into left field was less than 5%.

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc