In the diagram m angle acb = 61 find m angle bcd

Step-by-step explanation:

In the given diagram,

m(∠ACB) + m(∠ACf) +m(∠FCE) = 180°

[Angles formed at point on a straight line]

It is given that m(∠ACB) = 61°

                       m(∠ACF) = 90°

Therefore, 61° + 90° + m(∠FCE) = 180°

                 151 + m(∠FCE) = 180

                 m(∠FCE) = 180 - 151

                                 = 29°

Since m(∠FCE)  = (∠BCD)

[vertical opposite angles]

Therefore, m(∠BCD) = 29°

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb