Solve the inequality! (3x - 2)^2 - 4x(2x-3) greater or equal 0

Solve:

(3x-2)^2-4x(2x-3)>=0

(3x-2)(3x-2)-8x^2+12x>=0

9x^2-12x+4-8x^2+12x>=0

The solution: x^2+4>=0

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27 +27 or 27times 2=54

the diffrence is 0

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130