Every day, susan exercises in the morning. she travels a total of 4 miles. she starts off with a half-hour walk at a pace of 2 miles per hour. she then finishes while jogging at a pace of 6 miles per hour. write an equation that represents this situation, and use it to find the number of hours susan jogs at the increased speed.

Let's assume

the number of hours Susan jogs at the increased speed is 't' hours

Since, increased speed is 6 miles per hour

after 't' hours , she travles with increased speed is 6*t miles

She starts off with a half-hour walk at a pace of 2 miles per hour

so, she travels distance

=0.5*2 miles

=1 miles

She travels a total of 4 miles

total distance is

=6t+1

now, we can set them equal

now, we can solve for t

Subtract both sides by 1

Divide both sides by 6

we get

so, the number of hours Susan jogs at the increased speed is 0.5 hrs.........Answer

because they could drop even lower..

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: