Tom mowed lawns for the summer, in june he deposited $120 the first week, $80 the second week, and $75 the following week, then the mower needed repairs, so tom had to with-draw $30 from his account, how much money did he have left in his account at the end of june?

First, we need to figure out the total amount that was in his account...

$120 + $80 + $75 = $275

Now, we need to subtract $30 from $275

$275 - $30 = $245

Therefore, we had $245 dollars left in his account

Hope this helps

-AaronWiseIsBae

Tom had $245 left in his account at the end of June. $120+$80+$75=$275

$275-$30=$245

b

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.