The midpoint qr is m (-1,2). one endpoint is r (3,4). find the coordinates of the other endpoint.

M = (x₁ + x₂)/2  , (y₁ + y₂)/2

(-1, 2) =

At this point, it is easier to separate the x's and y's into two different equations:

x's: -1 =

     -2 = 3 + x

     -5 = x

y's: 2 =

     4 = 4 + x

     0 = x

(-5, 0)

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

its definatley   this on your answer choice?