What is the equation of the axis of symmetry for the parabola y=-1/2(x+3)^2-5

Now remember that the vertex's x-coordinate is the same as the axis of symmetry. In this case, looking at the vertex form equation, the vertex's x-coordinate is -3, therefore the equation for the axis of symmetry is x = -3.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

depends on how many days you are talking about

step-by-step explanation: