Find the equation of the line described. perpendicular to y = 6x + 5; passing through the point (3, 2).

Hello!

To find the line perpendicular to y = 6x + 5, you need to find -1/m. -1/m will give you the slope of the perpendicular line. After finding the slope, you need to substitute (3, 2) into the perpendicular without the y-intercept and solve for the y-intercept then.

In the given line, the slope is 6, or m = 6.

-1/m = -1/6

y = -1/6x + b

Now, we need to find the y-intercept.

2 = -1/6(3) + b

2 = -3/6 + b

2 = -1/2 + b (add -1/2 to both sides)

b = 5/2

Therefore, the equation of the line perpendicular to y = 6x + 5 is y = -1/6x + 5/2.

what is the question here

step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5