Arectangle has a length of x and a width of 5x^3 4-x^2. find the perimeter of the rectangle when the length is 5 feet.

Length (L): x                 ⇒ 5

width (w): 5x³ - 4x²   ⇒ 5(5)³ - 4(5)²   = 625 - 100   = 525

Perimeter (P) = 2L + 2w

                 P = 2(5) + 2(525)

                     = 10 + 1050

                     = 1060

1060 feet

1060 feet.

Step-by-step explanation:

We have been given that a rectangle has a length of x and a width of . We are asked to find the perimeter of rectangle when the length is 5 feet.

We know that perimeter of rectangle is two times the sum of length and width of rectangle.

Upon substituting , we will get:

Therefore, the perimeter of the rectangle is 1060 feet.

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

step-by-step explanation: