He service elevator in a high-rise building travels between the lowest underground parking level and the seventeenth story of the building. the lowest parking level is 15 meters below street level, and the seventeenth story is 51 meters above street level. if the elevator rises at a rate of 2 meters per second, how long, in seconds, could a person ride the elevator when starting from the lowest level? assume the elevator makes no extra stop. a.

First of all, we need to figure the TOTAL distance the elevator will travel from below street level to above street level. We know it's 15 meters below street level and 51 meters above street level, so let's add those two numbers.

51 + 15 = 66.

Now, we know the total distance the elevator will travel. We need to divide the distance that will be traveled by the rate of 2 meters per second.

66 / 2 = 33

There's your answer. The elevator will take 33 seconds to travel from the lowest story below street level to the highest story above street level.

A person could ride the elevator for a total of 33 seconds.

Hope this answer helped. :)

correct answer:

b.(19,-2)

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length