Abox contains 24 light bulbs, of which two are defective. if a person selects 10 bulbs at random, without replacement, what is the probability that both defective bulbs will be selected?

Solution: We are given that a box contains 24 light bulbs. 2 light bulbs are defective.

Now if a person selects 10 bulbs at random, without replacement.

We are required to find the probability that both defective bulbs will be selected.

Since there are two defective, therefore two defective can be chosen in ways.

Also since 10 bulbs are selected, the remaining 8 bulbs can be selected in

Also, the total number of ways 10 bulbs can be selected is:

Therefore, the probability that both defective bulbs will be selected is:

rounded to 4 decimal places

Hence, the probability that both defective bulbs will be selected is 0.1630

b.my answer is b.

brainliest

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )