Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6). a. (-1, 0), (3, 0) b. (-0.73, 0), (2.73, 0) c. (-1.48, 0), (2.48, 0) d. (-4.67, 0), (1.67, 0)

So firstly, plug the vertex into the vertex form:

Next, we first need to solve for a. Plug (0,-6) into the equation to solve for a as such:

Now we know that our equation is y = 3(x - 1)^2 - 9.

Now to solve for the zeros (x-intercepts). Set y to 0 and add 9 to both sides of the equation:

Next, divide both sides by 3:

Next, square root both sides:

Next, add 1 to both sides:

Your x-intercepts are (-0.73,0) and (2.73,0), or B.

12/11c

or

12

c

11

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2