Asoccer ball is kicked upward from a hill and then falls to the ground. the height, in feet, of the ball after t sec is modeled by the function h(t) = –16t2 + 26t +12. what is the initial height of the ball? –16 ft –12 ft 12 ft 22 ft mark this and return

For this case we have the following function:

Where,

t: is the time in seconds

h (t): is the height as a function of time

The initial height occurs when t = 0.

We have then:

The initial height of the ball is:

12 ft

step-by-step explanation:

if u want da anser kill your teeser ifu hav wun

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!