Set up an equation and solve. the width of a rectangle is 3 more than twice its length. the perimeter is 60 feet. find the width and length of the rectangle.

Length (L): 2w + 3

width (w): w

Perimeter (P) = 2L + 2w

                60 = 2(2w + 3) + 2(w)

                60 = 4w + 6 + 2w

                60 = 6w + 6

                54 = 6w

                  9 = w

  Length (L): 2w + 3   = 2(9) + 3   = 18 + 3   = 21

width = 9 feet, length = 21 feet