Determine which ordered pair is a solution of y = x + 2/5 (< that's a fraction and so are those down dere) (0,0) (1,2/5) (1,2/5) (2,2 2/5)

Plug the x and y-values into the given equation.  If it makes a true statement, then it is a solution.

y = x +

(0,0) → 0 = 0 +     FALSE

(1, ) →   = 1 +     FALSE

(2, 2 )  →  2 = 2 +     TRUE

(2, 2 )

child does not get an education so she can use the molla on junk

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!