Abox of bolts contains 8 thick bolts, 5 medium bolts, and 3 thin bolts. a box of nuts contains 6 that fit the thick bolts, 4 that fit the medium bolts, and 2 that fit the thin bolts. one bolt and one nut are chosen at random. what is the probability that the nut fits the bolt?

total bolts=21

total nuts= 12

no of way picking bolt and nut is= 21*12=252

no of way getting thick bolt and thick nuts = 9*7=63

no of way getting medium bolt and medium nut=8*3=24

no of way getting thin bolt and thin nut= 4*2=8

total ways=63+24+8=95

required probability= 95/252=0.3769

sorry not sure

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