Five gal of water are added to a pool each minute. after correctly carrying out the solve step of the five-step problem-solving plan, which solution should you arrive at to find the number of minutes that must pass until the pool contains 80 gal of water?

Simply divide 80 by 5. 5 goes into 80 16 times, and each 5 = one minuet, so it would take 16 minuets to fill the pool with 80 gallons.

What the other guy said. 10 = 2

So 10(2) 20(4) 30(6) 40(8) 50(10) 60(12) 70(14) and lastly. 80(16)

what the question so we can you out

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.