At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. at the same instant a truck, traveling with a constant speed of 8.50 m/s, overtakes and passes the automobile. (a) how far beyond the traffic signal will the automobile overtake the truck? (b) how fast will the automobile be traveling at that instant? (a) number entry field with correct answer 53.51851852 units entry field with correct answer

You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²

At the same time, a truck moving speed o 8.50 m/s passes the car

D=v.t (for the truck)

And d= v.t+1/2.a.t²(for the car)

v.t=1/2.a.t²

t=2.v/a

t=2.8.50 m/s/ 2.70 m/s²

17m/2.70=6.29

This mean that the distance is  

D=v.t=8.50m/s.6.29= 53.465 m/s

The speed of the car is  

Vcar=a.t

2.7m/s2×× 53.65

=144.34

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3

it would open into a square depending on the type of envelope i’m not sure about the second part