Use the frequency distribution to the right, which shows the number of voters (in millions) according to age, to find the probability that a voter chosen at random is in the given age range. not between 21 and 24 years oldbetween 21 and 24 years old ages of voters frequencyfrequency 18 to 20 8.68.6 21 to 24 11.611.6 25 to 34 21.221.2 35 to 44 22.822.8 45 to 64 58.358.3 65 and over 25.225.2 the probability is nothing. (round to three decimal places as needed.)

There are a total of 147.7 million voters, of which 11.6 million are in the 21–24 age range. The probability a randomly selected voter is in that range is

... 11.6/147.7 ≈ 0.079 . . . p(21–24)

The probability a voter is not in that range is

... 1 - p(21–24) ≈ 0.921

I find the question ambiguous as to what you want, so have provided numbers for both in-range and out-of-range. Use the one(s) you need.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.