Five identical bowls are labeled 1, 2, 3, 4, and 5. bowl i contains i white and 5 − i black balls, with i = 1, 2, . . , 5. a bowl is randomly selected and two balls are randomly selected (without replacement) from the contents of the bowl. a what is the probability that both balls selected are white? b given that both balls selected are white, what is the probability that bowl 3 was selected?

Probability of choosing bowl i = 1/5

Probability that first ball selected is white = i/5

Probability that second ball selected is white = i/4

(a) Probability that both balls selected are white:

           1/5 * i/5 * i/4 = isquared/100

(b) Probability that bowl 3 was selected is 1/5 + isquared/20

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).