Parallelogram wxyz has vertices w(0, 0) , x(1, 2) , y(4, 2) , and z(3, 0) . the parallelogram is dilated, and the vertices of the image are w'(0, 0) , x'(2, 4) , y'(8, 4) , and z'(6, 0) . the center of dilation is the origin. what is the scale factor of the dilation? enter your answer in the box. parallelogram wxyz was dilated by a scale factor of .

(0,0) is the origin of a graph, so both W and W' remain at the origin.

The other 3 vertices double in size:

If you multiply all the numbers in X, Y and Z by 2, they become the numbers in X', Y' and Z'.

X(1,2)  x 2 = (1*2,2*2) = X'(2,4)

Y(4,2) x 2 = (4*2, 2*2) = Y'(8,4)

Z(3,0) x 2 = (3*2, 0*2) = Z'(6,0)

That means the scale factor is 2

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2