Use the discriminant to determine the nature of the roots of the following equation. y2 - 5y - 3 = 0

Discussion

The discriminate is b^2 - 4*a*c

The general equation for a quadratic is ax^2 + bx + c

In this equation's case

a = 1

b= -5

c = - 3

Solve

(-5)^2 - 4*(1)*(-3)

25 - (-12)

25 + 12

37

Note

Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.

i dont have an answer

step-by-step explanation: