Two jets leave an airport at the same time in opposite directions. the first jet is traveling at 323 mph and the other at 347 mph. when will they be 1,541 miles apart?

Remark

This may be a little confusing, but because they are travelling in opposite directions, the distances add when you want to get how far apart they are.

d1 + d2 = 1541

Equation

Let the time this happens = t

d1 = 323*t

d2 = 347*t

323*t + 347*t = 1541 Combine like terms on the left.

670t = 1541 Divide by 670

t = 1541/670

t = 2.3 hours pass before the distance of 1541 miles are between the two planes. You might need the answer to be 2 hours 18 minutes.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

answer: b.36 feet

step-by-step explanation: