Aspinner with 3 sectors is shown in the figure below. the measures of the central angles of the red, white, and blue sectors, in that order, are in the ratio 2: 3: 4. if the spinner is fair, what is the probability that the arrow stops in the red sector? (note: assume the arrow stops in a sector and not on a line.) 112 29 13 49 59

Given that a spinner with 3 sectors. The measures of the central angles of the red, white, and blue sectors, in that order, are in the ratio 2:3:4.

So we can write:

Measure of the central angle of the red sector = 2x

Measure of the central angle of the white sector = 3x

Measure of the central angle of the blue sector = 4x

We know that sum of central angle of the circle is 360 degree so the sum of above three angles will also be 360 degree

2x+3x+4x=360

9x=360

x=40

Then measure of the central angle of the red sector = 2x=2*40= 80 degree

Measure of the central angle of the white sector = 3x=3*40=120 degree

Measure of the central angle of the blue sector = 4x=4*40=160 degree

We have to find the probability for red sector so first we need to find are of the red sector which is given by formula :

, where r is the radius of the spinner.

Area of the spinner is circular so that is given by

Area of spinner

Now the  probability that the arrow stops in the red sector is given by ratio or area of red sector and the area of spinner

Probability

Probability

Probability

Hence required probability is 2/9.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a