Asap 70 points question 1) d = {[x, f(x)]: (-1, 3), (0, 2), (1, 3), (2, 6), (3, 11)} write the rule for f(x). question 2) given: f(x) = 3x 2 + 1, g(x) = 2x - 3, h(x) = x f(-2) = question 3) given: f(x) = 3x 2 + 1, g(x) = 2x - 3, h(x) = x f(x) + g(x) =

question 1)

D = {[x, f(x)]: (-1, 3), (0, 2), (1, 3), (2, 6), (3, 11)} Write the rule for f(x).

when x = 0 , f(x) = 2

f(x) = x^2 + 2 this is the rule

question 2)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(-2) = 3(-2)^2 + 1 = 12 + 1 = 13

F(-2) = 13

question 3)

Given: F(x) = 3x 2 + 1, G(x) = 2x - 3, H(x) = x

F(x) + G(x) = 3x^2 + 1 + 2x - 3

F(x) + G(x) = 3x^2 + 2x - 2

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.