Miguel rodriguez borrowed $400 from his brother julio to pay for books and tuition. he agreed to pay julio in 6 months with simple annual interests at 6.8% how much will the interest amount to what amount must miguel pay julio at the end of 6 months

The simple interest is calculated as :

S.I = P*T*R

where S.I is the simple interest to be calculated

P = Principal

T = Time period in years

R = Annual interest rate

The the above problem,

Amount borrowed which would be the principal (P) = $400

Time period = 6 months = 1/2 year

Annual interest rate = 6.8% = 6.8/100 = 0.068

Simple Interest = P*T*R

Simple Interest = 400*1/2*0.068 = 200 *0.068

Simple Interest = $13.6

The simple interest amount that Miguel must pay to Julio at the end of six months is $13.6

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step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b