If`f(x)=2x^2-x-6` and `g(x)=x^2-4`, find `f(x)-: g(x)` . a. `(2x+3)/(x-2)` b. `(2x-3)/(x+2)` c. `(2x+3)/(x+2)` d. `(2x-3)/(x-2)`

First factor 2x² - x - 6 to get (2x +3)(x - 2)

Then place f(x) in the numerator and g(x) in the denominator.

(2x + 3)(x-2)

(x + 2)(x-2)

Cancel out (x-2) in the numerator and denominator

Then your answer will be (2x + 3)/(x + 2)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

b.

step-by-step explanation:

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