Not sure how to figure out how to get b2 by itself..can anyone me out?

As with any "solve for ..." problem, you start by looking at the operations performed on the variable of interest. Here, when you evaluate this expression according to the order of operations, you

When you want to solve for b2, you undo these operations in reverse order. To undo multiplication by a fraction, you multiply by the inverse (reciprocal) of the fraction. To undo addition, you add the opposite.

Whatever you do must be done to both sides of the equation.

Here we go ...

... (2/h)A = b1 + b2 . . . . . we undid the multiply by h/2, by multiplying by 2/h

... (2/h)A - b1 = b2 . . . . . we undid the addition of b1 by adding the opposite of b1

Then your solution is

... b2 = 2A/h - b1

If you want to, you can combine these terms over a single denominator to get

... b2 = (2A -h·b1)/h

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: