2e^3x=4e^5x. find x using log. show work

2 = 4

= 2divided both sides by 2

ln ( ) = ln (2 ) applied "ln" to both sides

ln ( ) = ln 2 + ln tex] e^{5x} [/tex] ) applied the log product rule

3x = ln 2 + 5x applied "ln e = 1"

-2x = ln 2 subtracted 5x from both sides

x = divided both sides by "-2"

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.