Two thirds of a number reduced by 11 is equal to 4 more than the number. find the number

2n/3 - 11 = n + 4

Add 11 to both sides:

2n/3 = n + 15

Multiply both sides by 3:

2n = 3n + 45

Isolate n:

-n = 45

n = -45

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

idkit the do u know da way and ligma consumed ninja

step-by-step explanation: