Who’s graph show a proportional relationship in which the value of y is one-half of the value of x

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

so

That means it's the equation of a line passing through the origin.

case a) and case d) are discarded because the line does not pass through the origin

case b) we have

for x=2 y=4

y/x=k-------> 4/2=2------> k=2

y=2x-------> in this case the value of y is two times the value of x

case c) we have

for x=4 y=2

y/x=k-------> 2/4=1/2------> k=(1/2)

y=(1/2)x-------> in this case the value of y is one-half of the value of x

therefore

the solution is the case c) see the attached figure

idk

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.