An image of two concentric circles is shown with r2 = 6 and r1 = 2: in order to prove the two circles are similar, the radius r2 was decreased to make the circles congruent. what is the scale factor used in the above image?

The radius of the Outer circle (with r₂) is 6 and the radius of the inner circle (with r₁) is 2. When objects are similar, they have a proportional relationship. If we take the outer circle and squeeze by one third, we get a radius of 6 x 1/3 = 2. On the other hand, if we start with the inner circle and stretch it by 3, we get a radius of 2 x 3 = 6.

Thus, to make r₂ similar, we use a scale factor of 1/3. The third choice is best.

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116