If two opposite sides of a square are increased by 15 meters and the other sides are decreased by 13 meters, the area of the rectangle that is formed is 60 square meters. find the area of the original square.

Let side of the square = x m, then:-

(x + 15)(x - 13) = 60

x^2 + 2x - 195 - 60 = 0

x^2 + 2x - 255 = 0

(x - 15)( x + 17) = 0

x = 15 meters (answer)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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