Two planes fly in opposite directions. one travels 450 mi/h and the other 550 mi/h. how long will it take before they are 4,000 mi apart?

The plane will take 4 hours.

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

It is the ratio of distance to time. and is given by,

Given

Two planes fly in opposite directions. one travels 450 mi/h and the other 550 mi/h.

The time takes before they are 4,000 mi apart.

We know the concept of relative speed, If speed is in opposite direction then it gets added up. then,

Speed = 450 + 550 = 1000

Then the time will be

The plane will take 4 hours.

More about the linear system link is given below.

link

Well there can be two different solutions for this but i will choose the easier one. Obviously one requires a system of equations which obviously will involve a lot of thinking and some good algebra solving in order for them to solve.

As for hit and trial it is very easy, we can just keep adding the distance as we know they are in different directions. 450 + 550 = 1000. So 1000 x 4 = 4000 miles. So after around 4 hours they will be 4000 miles apart if they continue at the same pace.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.