Points a, b,c are colinear on line segment ac , and ab: bc=3/4. a is located at (x, y) , b is located at (4,1) , and c is located at( 12,5). what are the values of x and y?

Given: Points A,B,C are co-linear on line segment AC , and

AB : BC = m : n= 3 : 4.

Coordinates of A = (x,y) ,

Coordinates of B = (x₁, y₁) = (4,1) , and

Coordinates of C = (x₂, y₂ ) = (12,5).

To find: the values of x and y

Now, we shall apply intersection (internally) formula for point B,

x₁ = (mx₂ + nx ) ÷ (m + n)

4 = (3×12 + 4× x ) ÷ (3 +4)  

or,       x = - 2  and,

y₁ = (my₂ + ny ) ÷ (m + n)

1 = (3×5 + 4× y ) ÷ (3 +4)  

or,       y = - 2

Hence, the required point A (x, y) will be (-2, -2)

answer: sine

step-by-step explanation: