Solve the equation -2x + 8 = -3x + 14.

Hello.

-2x + 8 = -3x + 14 = 6

-2x + 8= -3x + 14

It doesn't really matter where we start, but I started with adding 3x to both sides. When I do that, the new equation looks like

1x + 8= 14

I need to get x alone so I subtract 8 from both sides and get

1x = 6

X still isn't alone so I have to divide 1 on both sides.

Once I do that, it looks like

x=6

There's your answer!

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

34

step-by-step explanation: