Aprojectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t)=-16t^2 +704t. after how many seconds does the projectile take to reach its maximum height? show work

The easiest way in which this question could be answered is to find the x-coordinate of the vertex, which is also the equation of the axis of symmetry:

In this quadratic expression, a = -16 and b = 704.

The equation of the axis of symmetry is thus t = -b / (2a) = -704 / (2*(-16)) = 22.

The max height is attained after 22 sec.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.