Asample of 12 measurements has a mean of 34 and a standard deviation of 4.75. suppose that the sample is enlarged to 14 measurements, by including two additional measurements having a common value of 34 each. a. find the mean of the sample of 14 measurements. mean = 34 b. find the standard deviation of the sample of 14 measurements.

Following are the calculation to the Mean and standard deviation:

Given :

After adding additional two common values of 34 each.

For point a:

The mean of the sample of 14 measurements:

For point b:

The standard deviation of the sample of 14 measurements:

Therefore the final answer is "34 and 4.37".

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We start with 12 samples with an average of 34 and add two more samples of 34, so the mean remains 34.

For the variance (squared standard deviation) we add up the squared differences between the sample and the mean and divide by n-1=11. With two additional samples exactly at the mean, the sum won't change but now we divide by 13. So our new standard deviation must be

4.37

10cm

step-by-step explanation:

ik

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option