Write the equation of a line that passes through points (0,4) and (-2,-3) in slope intercept form

y=mx+b is the equation of a line;

m=slope , b= y-intercept

You can find the slope with this following equation: (y(2)-y(1))/(x(2)-x(1))

In this case the points are (0,4) and (-2,-3). The first set being (0,4) and the second (-2,-3). This means (0,4) can be expressed as (x(1),y(1)) and (-2,-3) expressed as (x(2),y(2)). Plugging these numbers into the slope equation gives us: (-3-4)/(-2-0) = -7/-2 = 7/2.

m= 7/2 ; so we have : y= (7/2)x+b

We are give a set of points which it passes through, we can simply plug them in:

4 = (7/2)(0)+b (0 is the x and 4 is the y)

We get 4 = 0 +b 4=b

our final equation is : y=(7/2)x+4

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