Solve (x + 5< 4) ∩ (x - 3 > -6) a. {x | -3 < x < -1} b. {x | x < -3 or x > -1} c. {all real numbers}

this is the answer

{ x | -3 < x < -1}

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

range is infinite on both x and y axis positive and negative

step-by-step explanation: