In the diagram below, triangle abc is an isoceles right triangle that overlaps square adef. ef=4 and ac=8. what is the ratio of the area of the quadrilateral edbc to the area of pentagon afecb? express your answer as a common fraction.

EDBC is a trapezoid

We know AC=8 and since the sides of an isosceles right triangle are in ratio

we conclude

We have a square so AD=ED=EF=4.

DB is the height of the trapezoid,

So the area of the trapezoid is

AFECB is the sum of two isosceles right triangles AFE + ABC so has area

That's a ratio of 8:24:8 or 1:3

That must mean that ADE and AFE each have area 8 as well.

1/3

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1