What is the equation of tha line , in general form, that passes through the point (1,1) and has a y-intercept of 2

The x-value at the y-intercept is 0. The y-value there is 2. As the x-value increases by 1 unit to x=1, the y-value decreases by 1 unit to y=1. Thus, the slope is -1, and the slope-intercept form of the equation can be written as

... y = -x + 2

Subtracting the right side puts the equation into general form.

... x + y - 2 = 0

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

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