If ray np bisects angle mnq and measure of angle mnq= 8x + 12 and measure of pnq= 78 degrees and measure of angle rnm= 3y -9, find the values of x and y

9514 1404 393

Step-by-step explanation:

Given:

  ∠MNP +∠PNQ = ∠MNQ = (8x+12)°

  ∠MNP = ∠PNQ = 78° = (3y-9)°

Find:

  x, y

Solution:

The overall angle measure is ...

  78° +78° = (8x +12)°

  78 = 4x +6 . . . . . . . . . divide by 2°

  72 = 4x . . . . . . . . . subtract 6

  18 = x . . . . . . . . divide by 4

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One angle measure is ...

  78° = (3y -9)°

  26 = y -3 . . . . . . divide by 3°

  29 = y . . . . . . . . add 3

The values of x and y are 18 and 29, respectively.

Comment on the question

We have interpreted the statement "angle RNM = 3y-9" to mean "angle PNM = 3y-9". This interpretation was chosen because point R is not mentioned or described anywhere else in the problem statement.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

if you divide 9 by 6 you will get 54.

- hope i .