Part a: if (6^2)x = 1, what is the value of x? explain your answer. part b: if (6^0)x = 1, what are the possible values of x? explain your answer.

In part A you have 6^2 = 36, then you have to find out what times 36 will get you to 1, you realize that 36*1/36 = 1. X=1/36

In part B: if 6^0 = 1, and 1x=1, you will realize that 1*1*1 =1. X=1.

Thanks have a good day/night <3

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step-by-step explanation: