Abag contains 15 new batteries and 10 used batteries. if heather randomly selects 2 batteries from the bag without replacement, what is the probability she will select a used battery and then a new battery? show work

well, 60% of 25 is 15, and 40% of 25 would be 10. So, it should be a 60-40 percent chance. so, the probability of an used one is lower than a new one by 20%

I may sound confusing so to sum it all up : It is lower than the new batteries because, the old ones would be a 40% chance while the new ones would be 60%.

There are 15 N (15 new batteries), and there are 10 U (10 used batteries)

The ratio is 3N : 2U

the chance of taking 1 N is 3/5 (60%)

the chance of taking 1 U is 2/5 (40%)

To grab both a new battery and an old battery multiply 3/5 * 2 / 5 = 6 / 25 (24%). To find the percentage from 6 / 25 multiply by 4 so the 25 becomes 100 and the 6 becomes the percentage, in this case 24 %.

24 %

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)